Philadelphia Eagles running back Saquon Barkley won the 2024 Offensive Player of the Year award last Thursday before winning Super Bowl LIX.
Cincinnati Bengals quarterback Joe Burrow, Bengals wide receiver Ja’Marr Chase, Baltimore Ravens running back Derrick Henry, and Ravens quarterback Lamar Jackson were the other finalists for the award.
Saquon Barkley claimed 406 points and 35 first-place votes, according to the Associated Press. He was followed by Jackson (183 points) and Chase (171).
Barkley excelled in his first season with the Eagles behind that amazing offensive line. He totaled 2,005 rushing yards, 278 receiving yards, and 15 total touchdowns. His rushing and scrimmage yard marks both led the NFL, even though he sat out the regular season finale with Philadelphia’s playoff seeding locked in.
Barkley, who turns 28 on Feb. 9, is just the eighth player to reach 2,000 rushing yards in a single season. He earned Pro Bowl and first-team All-Pro honors for his efforts this season, as well as becoming a Super Bowl Champion.
The 2018 first-rounder is the fourth running back to win Offensive Player of the Year since 2017. Former Los Angeles Rams runner Todd Gurley won the award in 2017, Henry took home the honor in 2020, and 49ers dual threat Christian McCaffrey was last year’s winner.
Jaden Chandler-Parnell, or “JC” is a Sports & Sports Betting Analyst for Stare Down Sports. You can Follow him on X @Jaden95Chandler
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